Python program to check whether the given number is an armstrong or not.

 

Given an integer,Write a python program to check if an integer is an Armstrong or not.

Armstrong

A given a number is said to be armstrong if the number of order or length n is digit*n times and the sum is equal to the number given

example - 153 = 1*1*1 + 5*5*5 +3*3*3

Example:

1. 153 - Armstrong

2. 345 - Not armstrong

3. 1634 - Armstrong

Python Program

#Check whether the given integer is an armstrong or not

#function for armstrong

def armstrong(n):

    #convert into str to calculate the order of the digit

    a = str(n)

    temp,sum= n,0

    while temp>0:

        #modulo by 10 to get each and every digit of a number

        digit = temp%10

        #multiply each digit with the order of the digit and sum the values

        sum+=digit**len(a)

        temp//=10

    #Print the result

    print("Armstrong") if sum==n else print("Not armstrong")

n = int(input())

#calling the armstrong function

armstrong(n)

 

Input:

153

Output:

Armstrong

Input:

345

Output:

Not armstrong